Question

ಒಂದು ಸಮಾಂತರ ಶ್ರೇಢಿಯಲ್ಲಿ nನೇ ಪದ an=4n+5 ಆದಾಗ ಶ್ರೇಢಿಯ 3ನೇ ಪದ / The nth term of an AP is an =4n+5 then find the 3rd term is *​

Answer 1

Answer:

nth term of an AP = a + (n - 1)d

a = first term .

d = common difference .

so,

→ a + (n - 1)d = 4n + 5

→ a + (n - 1)d = 4n - 4 + 4 + 5

→ a + (n - 1)d = 9 + 4n - 4

→ a + (n - 1)d = 9 + (n - 1)4

comparing we get,

a = 9

d = 4

therefore,

→ a3 = a + (3 - 1)d

→ a3 = 9 + 2*4

→ a3 = 9 + 8

→ a3 = 17 (Ans.)