Math, asked by wcody12155, 5 months ago

n art teacher had 2/3 gallon of paint to pour into containers. if he poured 1/8 gallon of paint into each container until he ran out of paint, how many containers had paint in them, including the one that was partially filled?

Answers

Answered by pmalachi336
0

Answer:

Seven  Mark Me Brainlies

Step-by-step explanation:

2/3 = .66... original partial gallon

1/8 = .125 other containers

So start pouring

5 of those 1/8s will give me .625, which isn’t quite there, so would need part of a 6th container for the little that’s left between .625 and .66..., (which is about 0.041666... gal., or (5.33 oz.))

Pour:

1) .125

2) .25

3) .325

4) .5

5) .625 ... not quite there

6) .66 - .625 = .035 to go in last container, or about 5 ounces.

so that’s 6 containers having paint poured into them,

PRESUMING ALL of the paint gets poured, then

6 containers “had paint in them.”

But in real life, paint sticks to the original container, and even scraping it out, there would still be SOME left in it.

So if it were a ‘container’ as well, then

7 containers “had paint in them”

Q: “An art teacher had 2/3 gallon of paint to pour into containers. If he poured 1/8 gallon of paint into each container until he ran out of paint, how many containers had paint in them, including the one that was partially filled?

Similar questions