Question

n(AUB)=51, n(B)=24, then find n(A-B)​

Answer 1

Answer:

n(AUB) = n(U) - n(AUB)’

n(AUB) = n(U) - n(AUB)’n(AUB) = 60 - 10

n(AUB) = n(U) - n(AUB)’n(AUB) = 60 - 10= 50

n(AUB) = n(U) - n(AUB)’n(AUB) = 60 - 10= 50Now,

n(AUB) = n(U) - n(AUB)’n(AUB) = 60 - 10= 50Now,n(AUB) = n(A) + n(B) - n(A∩B)

n(AUB) = n(U) - n(AUB)’n(AUB) = 60 - 10= 50Now,n(AUB) = n(A) + n(B) - n(A∩B)so,

n(AUB) = n(U) - n(AUB)’n(AUB) = 60 - 10= 50Now,n(AUB) = n(A) + n(B) - n(A∩B)so,n(A∩B) = n(A) + n(B) - n(AUB)

n(AUB) = n(U) - n(AUB)’n(AUB) = 60 - 10= 50Now,n(AUB) = n(A) + n(B) - n(A∩B)so,n(A∩B) = n(A) + n(B) - n(AUB)= 35 + 24 - 50

n(AUB) = n(U) - n(AUB)’n(AUB) = 60 - 10= 50Now,n(AUB) = n(A) + n(B) - n(A∩B)so,n(A∩B) = n(A) + n(B) - n(AUB)= 35 + 24 - 50= 9 is your answer…..