Question

n(AuB) = n(8) + n(6) - n(AnB)​

Answer 1

Step-by-step explanation:

n(AUB) = n(A) + n(B) - n(A∩B)

Also, If we subtract the Elements of set A from the Elements of Set B which are common to both the sets, then

n(A−B)=n(A)−n(A∩B) n(A−B)=n(A)−n(A∩B)n(A−B)=n(A)−n(A∩B)

Thus,

n(A∪B)=n(B)+n(A−B) n(A∪B)=n(B)+n(A−B)n(A∪B)=n(B)+n(A−B) ,

Therefore,

n(B)+n(A−B) n(A∪B)=n(B)+n(A−B)n(A∪B)=n(B)+n(A−B)

so as we know that….

n(A) = 5 , n(B) = 7

so answer will be 5

I hope it will help you

Follow me :)