n(AuB) = n(8) + n(6) - n(AnB)
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Step-by-step explanation:
n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)
Given n(A)=7
n(B)=9
n(A∪B)=14
Substituting in 1
14=7+9−n(A∩B)
⇒n(A∩B)=16−14=2
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