n(B) = 20, n(A ∩ B) = 10, n(A U B) =40, then find n(A) *
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Answered by
0
Answer:
n(A)=30
Step-by-step explanation:
n(A)+ n(B) -n(A∩B)=n(AUB)
let n(A) = x
x+20-10=40
x+10=40
x=40-10
x=30
hope this will help u
Answered by
0
Given that,
- n(B) = 20
- n(A ∩ B) = 10
- n(A U B) = 40
- n(A) = ?
Let,
- n(A) = x
We know that,
☯ n(A U B) = n(A) + n(B) - n(A ∩ B)
➡ 40 = x + 20 - 10
➡ 40 = x + 10
➡ x = 40 - 10
➡ x = 30
Step-by-step explanation:
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