n(B) =40 , n(A∩ B) =20, n( AU B)= 35, find n(A) *
Answers
Answered by
19
Answer:
∴ n(A) = 15
Step-by-step explanation:
Given,
n(B) = 40
n(AnB) = 20
n(AUB) = 35
To find:
n(A) = ?
from formula,
n(AUB) = n(A) + n(B) - n(AnB)
or, 35 = n(A) + 40 - 20
or, 35 = n(A) + 20
or, n(A) = 35 - 20
∴ n(A) = 15
Answered by
0
Answer:
Required value of n(A) is 15.
Step-by-step explanation:
We know,
This is a problem of set theory.By equation number (1),we can find n(B),n(A∩ B),n(A),n( AU B) alternatively.
For example,
Let n(B) =20 , n(A∩ B) =10, n( AU B)= 25
then
Here given,n(B) =40 , n(A∩ B) =20, n( AU B)= 35
From equation (1),
Required value of n(A) is 15.
Above formula only for 2 sets.
If there are three sets then
Similar questions