Question

n-block of different masses are placed on the frictionaless inclined plane in contact.They are released at the same time. The force of interaction between (n-1) th and nth block

Answer 1

Answer: mg sin theta

Explanation:

Answer 2

Answer:

Zero

Explanation:

Friction is absent on the incline surface So acceleration of each block is gsinθ. The FBD of n

th

block is shown in figure.

from Newton second law

m

n

gsinθ−T=m

n

a

m

n

gsinθ−T=m

n

(gsinθ)⇒T=0