n butane + alcl3 ki reaction kya hogi 300°c per
Answers
The mechanism for butane is shown here, instead of a general n-alkane.
Initiation
initiation
As the comments have mentioned, it probably begins by the protonation of butene impurities.
The Lewis acid, AlCl3, stabilizes the chloride ion from HCl when the H is used to protonate the butene.
A secondary carbocation is formed, which undergoes methyl shift to form a primary carbocation. I have no idea why a primary carbocation can be formed.
Propagation
propagation
An alkane attacks the carbocation, and supplies a "hydride" to the carbocation to complete the carbocation.
Meanwhile, another carbocation is formed which also undergoes methyl shift to regenerate the carbocation at the beginning of this step.
Termination
termation
I am going out of my way here to suggest a isobutyl chloride (1-chloro-2-methylpropane) termination product. I can't find other Lewis bases to complete the carbocation for the termination step.