Physics, asked by joelviju8673, 10 months ago

N -butane when treated with chlorine in the presence of uv light

Answers

Answered by 7siddharth0
1

Answer:

Explanation:

High intensity, broad-spectrum UV systems (also known as medium-pressure UV) reduce both free chlorine and combined chlorine compounds (chloramines) into easily removed byproducts. Between the wavelengths 180 and 400 nm, UV light produces photochemical reactions that dissociate free chlorine to form hydrochloric acid

Answered by Martin84
1

Explanation:

Ch3 -Ch2-Ch2Ch3 -> Ch3 -Ch2-Ch2ChCl + Hcl

chlorobutane and hydrochloric acid is formed.

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