Question

n capacitors each of capacitance C are connected in series. The effective capacitance is

Answer 1

for series connection of capacitors the formula to find the equivalent capacitance is 1/c1+1/c2+1/c3...=1/c(eq) (same as the formula for equivalent resistance in parall). For parallel connection of capacitors simply add up the capacitances i.e. c1+c2+c3....

Answer 2

The effective capacitance of the combination is $\dfrac{C}{n}$.

Explanation:

The equivalent capacitance in series combination is given by :

$\dfrac{1}{C_s}=\dfrac{1}{C_1}+\dfrac{1}{C_2}+....+\dfrac{1}{C_n}$

n capacitors each of capacitance C are connected in series.

$\dfrac{1}{C_s}=\dfrac{1}{C}+\dfrac{1}{C}+.....\text{n times }\\\\\dfrac{1}{C_s}=\dfrac{n}{C}\\\\C_s=\dfrac{C}{n}$

So, the effective capacitance of the combination is $\dfrac{C}{n}$.

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