N(CH3)3 is pyramidal but an N(SiH3)3 is Planner why
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N(SiH3)3 has a planar geometry due to back bonding between empty 3d orbital of Si and filled 2p orbital of N.
(CH3)3N has pyramidal geometry due to absence of back bonding. Nitrogen is sp3 hybridized out of which 3 hybrid orbitals are used for bond making and 1 lone pair is present in fourth orbital.
Hope it helps❤️❤️
(CH3)3N has pyramidal geometry due to absence of back bonding. Nitrogen is sp3 hybridized out of which 3 hybrid orbitals are used for bond making and 1 lone pair is present in fourth orbital.
Hope it helps❤️❤️
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