Question

(n) Complete the following activity to find the coordinates of a point on X-axis which is
equidistant from e (2, -5 ) and (-2,9). Let point M(x,0) on X-axis be equidistant
from the points
P(
25) and (-2,9).
PM - OM?
by distance formula,
(x-2) + (0-0)' = [(x-(-2)]++ (0-9)2
.. (x-2) + 52 - (x-2):O
x2 - 4x+0+25 = x2 + 4x+4+81
- 4x + 29 = 4x +85​

Answer 1

Step-by-step explanation:

(n) Complete the following activity to find the coordinates of a point on X-axis which is

equidistant from e (2, -5 ) and (-2,9). Let point M(x,0) on X-axis be equidistant

from the points

P(

25) and (-2,9).

PM - OM?

by distance formula,

(x-2) + (0-0)' = [(x-(-2)]++ (0-9)2

.. (x-2) + 52 - (x-2):O

x2 - 4x+0+25 = x2 + 4x+4+81

- 4x + 29 = 4x +85

the answer is 3,-1

thanks