Question

n drops each of radius 'r' and carrying a charge 'q' are combined to form a bigger drop. The ratio of potentials of bigger to that of smaller is

Answer 1

Explanation:

small drop radius = r

bigger drop radius = R

their are n small drops , collasce to form a bigger drop. volume remain constant

thus,

volume of small drop x n = volume of bigger drop

4/3 π r³ x n = 4/3 x π x R³

R = n⅓x r

potential of small drop , v = k q/r

potential of bigger drop ,V = k Q /R

= k ( nq) / n⅓ xr

= n⅔ k q/r = n⅔v

ratio, V/v = n⅔