Question

n factor of cu2s in
cu2s+o2=>cuo +so2​

Answer 1

Answer:

Explanation:

we know eqi. wt.= molar mass / n factor here molar mass = M { given } balance reaction cu2s + o2 = 2 cu2+ + so2 oxidation no of cu at cu2s= cu(6+) + s (-6) for 2 molecul for cu = 12 and product for 2 molecule of cu = 4 so n factor= Change in oxidation number/ mol n factor = 12 - 4/ 1 n factor= 8 equivalent wt = M/8

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