N factor of HNo3 will be
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In HNO3, the oxidation number of N is +5. ... In HNO3, the oxidation number of N is +5. If the product is NO in which the o.n. of N is +2, the change in oxidation number is of 3 units so eqv wt = mol wt/ 3 = 63/3 = 21. If the product is N2O, in which an N atom is in +1 state, so eqv wt = mol wt/ 4 = 63/4 = 15.75.
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hello friend here ur answer
Explanation:
N factor of HNo3 will be=4
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