Question

n-factor of k2cr2o7 in basic medium

Answer 1

Answer: N-factor for $K_2Cr_2O_7$ in basic medium is 3.

Explanation:

Potassium dichromate acts as a strong oxidizing agent in basic medium. The equation for potassium dichromate in basic medium follows:

$K_2Cr_2O_7+2NaOH\rightarrow K_2CrO_4+Na_2CrO_4+H_2O$

Net ionic equation follows:

$Cr_2O_7^{2-}+2OH^-\rightarrow 2CrO_4^{2-}+H_2O$

Oxidation state of Chromium in reactant side:

$\Rightarrow 2x-14=-2\\\Rightarrow x=+6$

Oxidation state of Chromium at product side:

$\Rightarrow x-8=-2\\\Rightarrow x=+6$

The oxidation state of chromium on product side is for 2 chromium atoms, hence for 1 chromium atom it will be $\frac{+6}{2}=+3$

As, the Oxidation state of chromium changes from +6 to +3.

Therefore, the n-factor for this atom will be (6 - 3) = 3