Question

n factor of Mg3N2 and equivalent ​

Answer 1

For salts, the value of valency factor is given by the net oxidation state on either cation or anion.

$\sf for \: \: Mg_3N_2 : \\ \sf charge \: on \:3(Mg {}^{2 + } ) \: or \:2(N {}^{3 - } ) \equiv6$

$\therefore\sf n_{f} = 6 \: eq ⋅\: {mol}^{ - 1}$

$\sf \implies E _{w} \approx \frac{3(24.3) + 2(14)}{6} = \frac{100.9}{6}$

$\sf \implies E_{w} \approx16.8167 \: g⋅ {eq}^{ - 1}$

And, approximating the mass of Mg as 24 g/mol

$\sf \: E_w \approx16.67 \: g⋅eq {}^{ - 1}$