Question

n fig. 2, in ADEF, if RS || EF, DR = 4x-3, DS = 8x - 7, ER - 3x - 1 and FS = 5x - 3, then the value of x is a) 2 b) 1 C) 8 d) 10
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Answer 1

Answer:

Step-by-step explanation:

DR = 4x-3, DS = 8x - 7, ER - 3x - 1 and FS = 5x - 3

4x-3/3x - 1 = 8x - 7/5x - 3

Or,24x²  −29x+7=20x² −27x+9

Or,4x²−2x−2=0

Or,2x²  −x−1=0

Or,2x(x−1)+1(x−1)=0

Or,(2x+1)(x−1)=0

Or,2x+1=0

x=-1/2 and x-1=0 or x=1

value of x 1

Answer 2

Answer:

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Step-by-step explanation:

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