Question

n figure, D is the mid-point of side BC of a ΔABC and ∠ABD = 50°. If AD = BD = CD, then the measure of ∠ACD is
) 70° b) 40° c) 30° d) 150°

Answer 1

Answer:

the correct answer is=40

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Answer 2

BAC = BAD + CAD

Since BD = AD

ABD = BAD

BAD = 50

ACD or ACB = CAD (since CD = AD)

CAD = ACD = x

ABC + BAC + ACB = 180 (angle sum property of∆)

50 + 50 + x + x = 180

100 + 2x = 180

2x = 80

x = 40

Hence angle ACD = x = 40

Correct option b) 40°