N has 13 factors smaller than N. Find the maximum number of factors of N ^ 3
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If N^2 has 13 factors smaller than N, what is the maximum number of factors of N^3?
The number N must be of the form:
N = a x b x c
The number of factors of N^2 is 27, out of which 13 are less than N and 13 are more than N.
Now maximum number of factors for N^3 would be: (3+1)(3+1)(3+1) = 64.
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