n identical cells each of EMF E and internal resistance R are connected in series find the expression for current in the circuit
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Answered by
28
Answer:
Current i = total emf/ total resistance
Since these are connected in series
Total emf = E + E +.. +E = nE
Total resistance = R+R+... +R = nR
Current, i = nE/nR = E/R
Answered by
7
Answer:
Current i = total emf/ total resistance
Since these are connected in series
Total emf = E + E +.. +E = nE
Total resistance = R+R+... +R = nR
Current, i = nE/nR = E/R
Explanation:
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