n In an A.P., if a = 1, tn = 20 and Sn = 462, then n is (A) 42 (B) 29 (C) 39 (D) 44
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Answer:
Step-by-step explanation:
Given that,
a = 1 , tn = 20 and Sn = 462
tn = a + ( n - 1 )d
20 = 1 + ( n - 1 ) d
20 - 1 = ( n - 1 ) d
( n - 1 ) d = 19
Sn = n/2 [2a + ( n - 1 ) d ]
462 = n/2 [ 2 ( 1 ) + 19 ] ( ∵ ( n - 1 )d = 19 )
462 × 2 = n [2+ 19 ]
924 = n [ 21 ]
n = 924 / 21
n = 44 is the answer.
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