Math, asked by nusrathalavi33, 7 months ago

n is a 4 digit number whose first two digits and last two digits are the same. n is also a perfect square. How many such numbers are possible?

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Answered by kapilchavhan223

0

Answer:

Consider four-digit numbers for which the first two digits are equal and the last two digits are also equal. How many such numbers are perfect squares? In order for this to be true, 100X + Y must be the product of 11 and a perfect square, and looks like X0Y. The only one that fits is 704......

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