Question

N is a 6 digits smalllest nmber which leaves 2 as a remainder in case when divided by 4,6, 10 and 15. Find the sum of all digits of the numbers

Answer 1

Answer:

5

Step-by-step explanation:

Let' s firstly take the LCM of 4, 6, 10, 15

After taking LCM of 4 ,6 ,10 ,15

you will get the answer 60

Least number of 6 digits = 100000

The leats number of 6 digits which is

exactly divisible by 60

= 100000 + (60 – 40) = 100020

∴ Required Number = 100020 + 2

= 100022

Now , let's do the sum of digits

= 1 + 0 + 0 + 0 + 2 + 2

= 5