Question

n is a natural number .square root of the sum of the square of n and 19 is equal to the next natural number to n.the value of n is.

Answer 1

$\sqrt{( {n}^{2} + 19)} = n + 1 \\ {n}^{2} + 19 = {n}^{2} + 2n + 1 \\ 2n + 1 = 19 \\ n = 9$
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