n is an integer such that 3n+4 <=19 and 10 n/n^2+16> 1. Find all the possible values of n
Answers
Answered by
2
n = {3 , 4 , 5} if n is an integer such that 3n+4 ≤ 19 and 10n/(n² + 16) > 1
Step 1:
Solve 3n+4 ≤19
Subtract 4 from both sides
3n ≤ 15
Divide by 3 both sides
n ≤ 5
Step 2:
Solve 10n/(n² + 16) > 1
as n² + 16 is +ve
Hence
n² + 16 < 10 n
=> n² - 10n + 16 < 0
=> (n - 8)(n - 2) < 0
=> 2 < n < 8
Step 3:
Combine both results
n ≤ 5 and 2 < n < 8
Hence 2 < n ≤ 5
n is an integer so n = {3 , 4 , 5}
Learn More:
Solve the following x+y/xy=5 and x-5/xy=7 - Brainly.in
brainly.in/question/8168066
solve for x and y : x+y/xy=2,xy/=6
brainly.in/question/12892518
Similar questions