N is the least integer which leaves remainder of 2, 4, 6 when divided by the divisors 10, 12, 14 respectively. Find the remainder when divided by 19.
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Let us first find the factors of the given numbers 20,25,35 and 40 to find the LCM of these numbers:
20=2×2×525=5×535=5×740=2×2×2×5
Therefore, LCM(20,25,35,40)=5×5×2×2×2×7=1400
Now we find the difference of the given numbers as follows:
20−14=6, 25−19=6, 35−29=6 and 40−34=6
So, we get 6 less than the divisor in each case and thus the required number is 1400−6=1394
Hence, the number is 1394.
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