Math, asked by abubblygirl, 17 hours ago

n Δ LMN, LM = 5 cm, MN = 6 cm, LN = 7 cm, If Δ LMN ~ Δ ABC and AB = 10 cm, then find the length of remaining sides of Δ ABC.​

Answers

Answered by HumairaSultana
1

Step-by-step explanation:

LMN ~ABC

therefore corresponding side will be propotional

AB/LM=10/5=2cm

BC/MN= x/6 =6×2/6=12/6=2cm

CD/LN= 7×2/7=14/2=2cm

therefore

BC=12cm

CD=14cm

Answered by vennampalli1969
1

Answer:

1. Draw LN=7cm.

1. Draw LN=7cm.2. With L as centre and radius =6.4cm, draw an arc at M.

1. Draw LN=7cm.2. With L as centre and radius =6.4cm, draw an arc at M.3. With N as centre and radius =5.5cm, draw an arc at M.

1. Draw LN=7cm.2. With L as centre and radius =6.4cm, draw an arc at M.3. With N as centre and radius =5.5cm, draw an arc at M.4. Join LM, MN.

1. Draw LN=7cm.2. With L as centre and radius =6.4cm, draw an arc at M.3. With N as centre and radius =5.5cm, draw an arc at M.4. Join LM, MN.5. Hence Δ LMN is the required triangle.

Step-by-step explanation:

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