N moles of gas filled in a container at temperature t is in equilibrium initially.If the gas is compressed slowly and isothermally to half its initial volume the workdone by the atmosphere on the piston is
Answers
Answered by
4
Hey dear,
● Answer-
-NRt.ln(2)
● Explaination-
# Given-
∆T = 0
V2 = 1/2 V1
# Solution-
For an isothermal process at constant pressure, work done in changing volume from V1 to V2 is given by-
W = NRt.ln(V2/V1)
W = NRt.ln(V1/2V1)
W = NRt.ln(1/2)
W = -NRt.ln(2)
Work done by the atmosphere on the piston is -NRt.ln(2) .
Hope this is useful...
Answered by
0
Answer: –nRTLn2
Explanation:
work done in isothermal process
:nRTLn(V2/V1)
A/c to Que. V2=V1/2
So, W. D=nRTLn(1/2)
= –nRTLn2
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