Question

N monkeys are invited to a party where they start dancing. They dance in a circular formation, very similar to a Gujarati Garba or a Drum Circle. The dance requires the monkeys to constantly change positions after every 1 second. The change of position is not random & you, in the audience, observe a pattern. Monkeys are very disciplined & follow a specific pattern while dancing. Consider N = 6, and an array monkeys = {3,6,5,4,1,2}. This array (1-indexed) is the dancing pattern. The value at monkeys[i], indicates the new of position of the monkey who is standing at the ith position. Given N & the array monkeys[ ], find the time after which all monkeys are in the initial positions for the 1st time

Answer 1

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Answer 2

Answer:

def position(num):

   y=num

   x=[0]*len(num)

   count=0

   while(x!=num):

       count+=1

       x=[0]*len(num)

       for i in range(len(num)):

           x[num[i]-1]=y[i]

       y=x

   return count

n=int(input())

for i in range(n):

   number=int(input())

   monkey=list(map(int,input().split()))

   r=position(monkey)

   print(r)

Step-by-step explanation: