n(n-1)/2=6 find value of n?
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Answer:
-3 or 4
Explanation:
n(n-1)/2=6
n(n-1)=6*2
n^2-n =12
n^2-n-12=0
now, as we know factors of 12 is 3 and 4 and difference between two factors is 1.
hence
n^2-4n+3n-12=0
n(n-4)+3(n-4)=0
(n-4)(n+3)=0
So, n= -3 or 4
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