n(n+1)(n+5),number 3's multiple
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(n+1)(n+5)=n²+5n+n+5
so, n×(n+1)(n+5)=n³+5n²+n²+5n
=n³+6n²+5n
upon Solving this You wuold Get the above answer.
is this what You were Looking for???
so, n×(n+1)(n+5)=n³+5n²+n²+5n
=n³+6n²+5n
upon Solving this You wuold Get the above answer.
is this what You were Looking for???
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