n(n-3)=18. Solve for n.
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n=6 , n= -3
n(n-3)=18
n^-3n=18
n^-3n-18=0
n^-6n+3n-18=0 [ by factorisation]
n(n-6)+3(n-6)=0
(n-6),(n+3)=0
n-6=0,n+3=0
n=6,n= -3
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