Math, asked by kraokorrapati, 11 months ago

n(n-3)=18. Solve for n.

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Answered by Anonymous
2

hope it will help you....

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Answered by akashhiremath001
1

n=6 , n= -3

n(n-3)=18

n^-3n=18

n^-3n-18=0

n^-6n+3n-18=0 [ by factorisation]

n(n-6)+3(n-6)=0

(n-6),(n+3)=0

n-6=0,n+3=0

n=6,n= -3

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