{n(n-3)}/2=2 find the value of n .....
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n(n-3) / 2 = 2
n^2 - 3n / 2 = 2
n^2 - 3n =4
n^2 - 3n - 4 = 0
n^2 - 4n + n - 4 = 0
n(n-4) +1(n-4) = 0
(n+1)(n-4) = 0
so, n= -1
n=4
n= 4 answer.
hope it's help you ✌✌
n^2 - 3n / 2 = 2
n^2 - 3n =4
n^2 - 3n - 4 = 0
n^2 - 4n + n - 4 = 0
n(n-4) +1(n-4) = 0
(n+1)(n-4) = 0
so, n= -1
n=4
n= 4 answer.
hope it's help you ✌✌
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Answered by
1
Answer:
Step-by-step explanation:
{n(n-3)}=4
n.n-3n=4
n^2-3n-4=0
n^2-4n+n-4=0
n(n-4)+1(n-4)=0
(n-4)(n+1)=0
n-4=0
n=4
n+1=0
n=-1
n=4,-1
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