Question

n[n!+(n-1)!]+n²(n-1)!+(n+1)!​

Answer 1

Step-by-step explanation:

2

+2

2

+3

2

+......+n

2

=

6

n(n+1)(2n+1)

To prove: 1

2

+2

2

+3

2

+......+n

2

>

3

n

2

But, 1

2

+2

2

+3

2

+......+n

2

=

6

n(n+1)(2n+1)

⇒ To prove

6

n(n+1)(2n+1)

>

3

n

2

If we put n=1 , we get,

6

1(1+1)(2+1)

>

3

1

2

1>

3

1

⇒1

2

+2

2

+3

2

+......+n

2

>

3

n

........

Hope it's helps...

Answer 2

Answer:

your answer is in the attachment

Step-by-step explanation:

hope it's help you XD