N+= N++ * ++N – (N++ + N) if int N = 12 in java
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✌
Explanation:
++n increments the value and returns the new one.
n++ increments the value and returns the old one.
Thus, n++ requires extra storage, as it has to keep track of the old value so it can return it after doing the increment.
I would expect the actual difference between these two to be negligible these days. I know a lot of compilers will optimize it so they're identical if the return of n++ isn't actually used, though I don't know of Java does that
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