+
N = NBF4
Δ
→ A
In the above process product, A is
(a) Fluorobenzene
(b) Benzene
(c) 1, 4-difluorobenzene
(d) 1, 3-difluorobenzene
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1
Answer:
option (a). --- fluorobezene
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The correct answer will be option a , Fluorobenzene .
- Firstly, Benzene diazonium chloride is treated with hydro fluoroboric acid (HBF4) to form Benzene Diazonium fluoroborate.
- This is then heated to form fluorobenzene giving dinitrogen and boron trifluoride as by-products.
- This reaction of producing fluorobenzene from benzene diazonium salt is called Schiemann-Balz reaction.
- Instead of HBF4, NaBF4 can also be used to produce Benzene Diazonium fluoroborate
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