n object moves with a uniform speed of 10meterspersquare for 5sec calculate the distance travelled find the distance
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Explanation:
The initial velocity is u=0ms−1
The acceleration is a=10ms−2
The time is t=5s
Apply the equation of motion
v=u+at
The velocity is
v=0+10⋅5=50ms−1
The distance travelled in the first 5s is
s=ut+12at2
=0⋅5+12⋅10⋅52=125m
The distance travelled in the following 10s is
s1=vt1=50⋅10=500m
The total distance travelled is
d=s+s1=125+500=625m
Hope this helps you
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