N object weighing 20n in air weighs 10n in water. Find the volume of the object. (density of water = 997 kg/m
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Given Data:
997— density of water
1 m3 = 1 unit volume
10 m/s2— acceleration of gravity.
Equation for liquid:
W=mg…20 = m
mass= 10 = (1000kg/m3)*V*10 m/s2
Submerged Volume in liquid:
V=
Equation for air:
W=mg…10 =m* 10
mass=1.02 kg
10 =(997kg/m3)*V*9.81 m/s2
Submerged Volume in air:
V=
997— density of water
1 m3 = 1 unit volume
10 m/s2— acceleration of gravity.
Equation for liquid:
W=mg…20 = m
mass= 10 = (1000kg/m3)*V*10 m/s2
Submerged Volume in liquid:
V=
Equation for air:
W=mg…10 =m* 10
mass=1.02 kg
10 =(997kg/m3)*V*9.81 m/s2
Submerged Volume in air:
V=
Answered by
0
volume of water =997kg/M3
mass exerted. 10n
let volume be v
997=10n/v
v=10n/997
v=0.01n
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