n open rectangular tank of length 0.2m and breadth 0.15m contains water to a height of 0.16m find
1• the volume of water in the tank,(giving your answer in liters)
2• the surface area of the tank that is in contact with the water.
Answers
Answered by
13
Answer:
1• Volume = lbh = 0.2×0.15×0.16 = 0.0048 cubic.m.
2• TSA = 2(lb+bh+hl) = 2[(0.2)(0.15)+(0.15)(0.16)+(0.2)(0.16)] = 0.116 sq.m
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Answered by
6
Answer:
Volume = L x B x H = 0.2 x 0.15x 0.16
=0.0048m³
Surface Area = 2 (LB + LH + BH)
= 2 (0.03 + 0.032 + 0.024)
= 2 (0.086)
= 0.172m²
Step-by-step explanation:
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