Question

n[P(A)]=1024,n(AUB)=15,n[P(B)]=32 find n(AnB)

Answer 1

n(AUB) =n(A) +n(B)-n(AnB)
15=1024+32-n(AnB)
15=1056-n(AnB)
n(AnB)=1056-15
=1041 is answer obtained