N-P-N transistor with current gain 100 is used
38.) In the following common emitter configuration an
The output voltage of the amplifier will be
2012
10 kg
1 ko
1 mv
V
T
3 (1) 10 mV
(3) 1.0 V
(2) 0.1 V
(4) 10 V
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Answer:
β=iBiC=100
IC=100×1kΩ10mV=1mA
∴Vo=IC×Ro=1mA×10kΩ=10V
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