N permutation two is equal to seventy-two
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Answer:
n
2
p
=72
\frac {n!}{(n-2)!} = 72
(n−2)!
n!
=72
\frac {n \times (n-1) \times (n-2)!}{(n-2)!} = 72
(n−2)!
n×(n−1)×(n−2)!
=72
n \times (n-1) = 72n×(n−1)=72
n^2 - n - 72 = 0n
2
−n−72=0
n^2 -9n + 8n -72 = 0n
2
−9n+8n−72=0
(n-9) =0, (n+8) =0
n = 9,-8
We take (+) Values
So, value of Combination as well as Permutations is 9
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