^n Pr *x^nC r then x us equal to __________
Answers
Answered by
0
Answer:
When
r
=
1
,
x
=
n
; When
r
=
0
,
x
=
1
Explanation:
I think
x
is the point where we have
n
P
r
=
n
C
r
so I'll assume that to be the case.
Where we have this relation, we have:
n
!
(
n
−
r
)
!
=
n
!
(
k
!
)
(
n
−
r
)
!
We can divide through by
n
!
(
n
−
k
)
!
to get to:
1
=
1
r
!
r
!
=
1
⇒
r
=
1
,
0
Does this work?
Let's have a test case of
n
=
5
,
r
=
1
:
5
!
4
!
=
5
!
(
1
!
)
(
4
!
)
=
5
And now a test case of
n
=
5
,
r
=
0
:
5
!
5
!
=
5
!
(
5
!
)
(
0
!
)
=
1
And so we end up with 2 cases:
When
r
=
1
,
x
=
n
When
r
=
0
,
x
=
1
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