n-propyl iodide reacts with NaOCH2-CH3 (Sodium ethoxide) to give? *
• CH3-O-CH2-CH3
• CH3-CH2-O-CH2-CH3
• CH3-O-CH2-CH2-CH3
• CH3-CH2-O-CH2-CH2-CH3
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The answer to the question is the last option Ch3-Ch2-O-Ch2-Ch2-Ch3
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