Question

n root a × root 3 = 6 root 108 then n+a =​

Answer 1

Answer:

Here's your answer!!

Here are some steps.

First, we rewrite 108 as a product of a perfect square and another number. Notice that 108 is divisible by 4, and 4 is a perfect square, so we can rewrite 108 as 4 x 27.

V(108) = V( 4 27)

Now, write the square root as a product of square roots using our rule.

4 27) = x(4) x(27) Next, we evaluate (4) as 2.

V(4) x(27) = 2 x V(27)

Now, we start over for v(27). We can rewrite 27 as 9 x 3, where 9 is a perfect square, then take it through our steps.

V(108) = 2 x v(27) = 2 x v(9 x 3) = 2 x v(9) x v(3) = 2 x 3 x v(3) = 6 x(3)

Since 3 doesn't have any perfect square factors, V(3) is as simplified as possible, so we have that the square root of 108 in radical form is 6 x v(3), 6v(3).