Question

N small conducting liquid droplets, each of radius r, are charged to a
potential V each. These droplets coalesce to form a single large drop
without any charge leakage. Find the potential of the large drop-​

Answer 1

Answer:

Let potential of 1 drop =

r

Kq

=V

Volume of n drops = volume of bigger drop

i.e., n

3

4

πr

3

=

3

4

πR

3

Therefore, R=n

3

1

r

Also charge remains conserved

Charge on 1 drop = q

Charge on big drop containing n drops = nq

Therefore potential on big drop = K

n

3

1

r

nq

= n

3

2

r

Kq

= n

3

2

V