Physics, asked by puspalatamohapatra7, 7 months ago

n small drops of mercury, each of radius r and
charge q, coalesce to form a big drop. The ratio of
surface charge density of small drop with that of
the big drop is?​

Answers

Answered by satvinderrana911
1

Answer:

64 small drops of mercury each of radius r and charge q coalesce to form a big drop. The ratio of the surface charge density of each small drop with that of big drop is. (A) 4:1.

Similar questions