n small Mercury drops of same size are charged to V volts each. If they coalesce to for a single drop then it's potential will be?
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The potential of the drops after coalescing will be equal to V×(n^2/3).
- We use a conservation of volume followed by conservation of charge before and after the coalescing takes place in order to get the radius and charge of the new sphere formed with respect to the smaller spheres.
- Then we use that potential for a sphere is equal to k×q/r.
- Comparing the potential by taking their ratio we finally get our desired result.
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